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Summary
Description |
English: Simplified version of similar triangles proof for Pythagoras' theorem.
In triangle ACB, angle ACB is the right angle. CH is a perpendicular on hypotenuse AB of triangle ACB. In triangle AHC and triangle ACB, ∠AHC=∠ACB as each is a right angle. ∠HAC=∠CAB as they are common angles at vertex A. Thus triangle AHC is similar to triangle ACB by AA test. Thus,
In triangle BHC and triangle ACB, ∠BHC=∠ACB as each is a right angle. ∠HBC=∠CBA as they are common angles at vertex B. Thus triangle BHC is similar to triangle BCA by AA test. Thus,
which is the Pythagoras theorem.
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Date |
2012-05-15 10:08 (UTC) |
Source |
This file was derived from:
Reference:
- ↑ (2011) GEOMETRY Standard X, Secretary, Maharashtra State Board of Secondary and Higher Secondary Education, Pune-411 004, pp. 22, 23
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Author |
- derivative work: Gauravjuvekar
- derivative work: Gauravjuvekar
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✓ The source code of this SVG is valid.
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This is a retouched picture, which means that it has been digitally altered from its original version. Modifications: Simplified and removed lower-case notations and related elements per some comments at Wikipedia:Featured picture candidates/Pythagoras similar triangles proof. The original can be viewed here: Pythagoras_similar_triangles.svg. Modifications made by Gauravjuvekar.
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Licensing
Public domainPublic domainfalsefalse |
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This image of simple geometry is ineligible for copyright and therefore in the public domain, because it consists entirely of information that is common property and contains no original authorship.
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